The rate equation for the acid-catalysed reaction between iodine and propanone is: rate = k [H+] [C3H6O] The rate of reaction was measured for a mixture of iodine, propanone and sulfuric acid at pH = 0.70 In a second mixture the concentration of the sulfuric acid was different but the concentrations of iodine and propanone were unchanged. The new rate of reaction was a quarter of the original rate. What was the pH of the second mixture?

Source: · 27 · 2017